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17 March, 06:37

An automobile traveling along a straight road increases its speed from 30.0 m/s to 50.0 m/s in a distance of 180 m. If the acceleration is constant, how much time elapses while the auto moves this distance

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  1. 17 March, 08:11
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    4.5sec

    Explanation:

    From the question above, the following are the parameters that are given

    u = 30m/s

    v = 50m/s

    s = 180m

    First of all we have to find the acceleration by using the third equation of motion

    V^2 = U^2 + 2as

    50^2 = 30^2 + 2 (a) (180)

    2500 = 900 + 360a

    Collect the like terms

    2500-900 = 360a

    1600=360a

    Divide both sides by the coefficient of a which is 360

    1600/360=360a/360

    a = 4.44m/s

    The next step is to find the time. To do this we will have to use the first equation of motion

    v = u + at

    50 = 30 + 4.44t

    Collect the like terms

    50-30 = 4.44t

    20 = 4.44t

    Divide both sides by the coefficient of t which is 4.44

    20/4.44 = 4.44t/4.44

    t = 4.5sec

    Hence 4.5secs elapses while the auto moves at a distance of 180m
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