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3 February, 06:34

The specific heat of a 101 g block of material is to be determined. The block is placed in a 25 g copper calorimeter that also holds 60 g of water. The system is initially at 20°C. Then 125 mL of water at 80°C are added to the calorimeter vessel. When thermal equilibrium is attained, the temperature of the water is 54°C. Determine the specific heat of the block.

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  1. 3 February, 10:08
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    c = 0.329 cal/g. K

    Explanation:

    total Heat released = mass x specific heat capacity of water x temperature change

    = 125 x 1 x (80 - 54) = 3250 cal

    Heat absorbed by material = mass x specific heat capacity of material x temperature change

    = 101 x c x (54 - 20) = 3434*c cal

    Heat absorbed by calorimeter = mass x specific heat capacity of Cu x temperature change

    = 25 x 0.092 x (54 - 20) = 78.2 cal

    Heat absorbed by water = mass x specific heat capacity of water x temperature change

    = 60 x 1 x (54 - 20) = 2040 cal

    Conservation of energy requires total heat absorbed = total heat released

    3434*c + 78.2 + 2040 = 3250

    c = 0.329 cal/g. K
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