If san andreas fault slips 2.5 cm each year how far would it separate in 100 years

250cm or 2.5m

Explanation:

using direct variation

the length is = l

the time (year) = t

let k be the constant

so he have:

l=kt

2.5=k * 1

k = 2.5

Now in the next statement the 100 is given but not the length so

l=kt

~ l=k * 100 years

But k = 2.5

so:

l = 2.5*100

l = 250 cm

Hence it will be 250cm or 2.5m at which they will get separated