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30 August, 05:33

An electron and a proton have charges of an equal magnitude but opposite sign of 1.6 x 10-19 C. If an electron and proton in a hydrogen atom are separated by a distance of 5 x 10-11 m, (a) what is the magnitude of the force exerted on the electron by the proton?

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  1. 30 August, 05:56
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    9.216 x 10^-8 N

    Explanation:

    q1 = 1.6 x 10^-19 C

    q2 = - 1.6 x 10^-19 C

    r = 5 x 10^-11 m

    (a) The electrostatic force is given by

    F = k q1 q2 / r^2

    F = (9 x 10^9 x 1.6 x 10^-19 x 1.6 x 10^-19) / (5 x 10^-11) ^2

    F = 9.216 x 10^-8 N

    This force is attractive in nature, as both the charges are opposite in nature.
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