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13 May, 07:19

A boy throws a ball straight up in the air with an initial velocity of V+3 mls. The ball reaches a maximum height and starts towards earth. The boy catches the ball at the same height that it left his hand. How long is the ball in the air? 6. a.) = 1.01 s b.) t-0.61s c.) 1-2.32s d.) t=1.23h e.) None of the above.

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  1. 13 May, 09:21
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    Option (b)

    Explanation:

    Let the ball takes time t to reach the maximum height. The final velocity at maximum height is zero.

    Use I equation of motion, we get

    V = u + gt

    0 = 3 - 9.8 x t

    t = 0.306 s

    As the air friction is negligible, so the ball takes same time to reach the hand of boy. Thus the time taken by the ball in air is

    T = 2 t = 2 x 0.306 = 0.61 s
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