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29 July, 22:20

Determine the position in which a solid cylindrical block of wood of diameter 0.3 m and length 0.4 m will float in water. Take specific gravity of wood as 0.5

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  1. 29 July, 22:30
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    0.2 m

    Explanation:

    Diameter = 0.3 m

    radius, r = 0.15 m

    Length, H = 0.4 m

    density of wood, d = 0.5 g/cm^3 = 500 kg/m^3

    density of water, d = 1000 kg/m^3

    Let h be the depth of cylinder immersed in water.

    By the principle of floatation.

    Buoyant force = Weight of cylinder

    Volume immeresed x density of water x g = Volume of cylinder x density of wood x g

    A x h x 1000 x g = A x H x 500 x g

    1000 h = 500 x 0.4

    h = 0.2 m
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