Ask Question
30 January, 10:39

A goose with a mass of 2.0 kg strikes a commercial airliner with a mass of 160,000 kg head-on. Before the collision, the goose was flying with a speed of 60 km/hr and the aeroplane's speed was 870 km/hour. Take the length of the goose to be 1.0 m long. (a) What is the change in momentum of the goose during this interaction?

+5
Answers (1)
  1. 30 January, 12:30
    0
    The change in momentum of the goose during this interaction is 33.334 m/s

    Explanation:

    Given;

    mass of goose, m₁ = 2.0 kg

    mass of commercial airliner, m₂ = 160,000 kg

    initial velocity of the bird, u₁ = 60 km/hr = 16.667 m/s

    initial velocity of the airliner, u₂ = 870 km/hr = 241.667 m/s

    Change in momentum is given as;

    ΔP = mv - mu

    where;

    u is the initial velocity of the bird

    v is the final velocity of the bird

    Apply the principle of conservation of linear momentum;

    Total momentum before collision = Total momentum after collision

    m₁u₁ + m₂u₂ = v (m₁ + m₂)

    where;

    v is the final velocity of bird and airliner after collision;

    (2 x 16.667) + (160,000 x 241.667) = v (2 + 160,000)

    38,666,753.334 = 160,002v

    v = 38,666,753.334 / 160,002

    v = 241.664 m/s

    Thus, the final velocity of the bird is negligible compared to final velocity of the airliner.

    ΔP = mv - mu

    ΔP = m (v - u)

    ΔP = 2 (0 - 16.667)

    ΔP = - 33.334 m/s

    The negative sign implies a deceleration of the bird after the impact.

    Therefore, the change in momentum of the goose during this interaction is 33.334 m/s
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A goose with a mass of 2.0 kg strikes a commercial airliner with a mass of 160,000 kg head-on. Before the collision, the goose was flying ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers