After a party the host pours the remnants of several bottles of wine into a jug. He then inserts a cork with a 2.25-cm diameter into the jug, placing it in direct contact with the wine. He is amazed when he pounds the cork into place that the bottom of the jug, with a 16.5-cm diameter, breaks away. show answer No Attempt Find the force that the liquid exerts on the bottom of the bottle when the host is pounding the cork with a 150-N force. Ignore the force caused by the weight of the wine.

Question

Physics

Khan

17 February, 21:05

After a party the host pours the remnants of several bottles of wine into a jug. He then inserts a cork with a 2.25-cm diameter into the jug, placing it in direct contact with the wine. He is amazed when he pounds the cork into place that the bottom of the jug, with a 16.5-cm diameter, breaks away. show answer No Attempt Find the force that the liquid exerts on the bottom of the bottle when the host is pounding the cork with a 150-N force. Ignore the force caused by the weight of the wine.

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Answers (1)

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Levi · Answer 1

F = 8066.67 N

Explanation:

The extra force exerted on the bottom of the jug can be expressed as the pressure generated by the cork multiplied by the area of the bottom. We can also obtain the Pressure P by dividing the force F1 applied to the cork by it's area A1.

Thus;

F = PA2 = (F1/A1) x (A2)

F = (F1 / (πd1²/4)) x (πd2²/4)

π/4 will cancel out to give;

F = F1 (d2/d1) ²

F = 150 (16.5/2.25)

F = 8066.67 N