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2 August, 03:49

A small glass bead has been charged to 7.6 nC. What is the magnitude of the electric field 2.0 cm from the center of the bead? (k = 1/4πε 0 = 8.99 * 109 N · m2/C2)

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  1. 2 August, 07:49
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    1.7 * 10^8 N/C

    Explanation:

    Q = 7.6 nC, r = 2 cm = 0.02 m

    E = KQ/r^2

    E =

    8.99 * 10^9 * 7.6 * 10^ (-6) / (0.02 * 0.02)

    E = 1.7 * 10^8 N/C
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