The specific heat of a certain type of metal is 0.128 J / (g⋅∘C).0.128 J / (g⋅∘C). What is the final temperature if 305 J305 J of heat is added to 94.0 g94.0 g of this metal, initially at 20.0 ∘C?

45.3°C

Explanation:

Heat gained = mass * specific heat * increase in temperature

q = mC (T - T₀)

Given C = 0.128 J/g/°C, m = 94.0 g, q = 305 J, and T₀ = 20.0°C:

305 J = (94.0 g) (0.128 J/g/°C) (T - 20.0°C)

T = 45.3°C