Ask Question
3 May, 16:16

To practice Problem-Solving Strategy 11.1 for conservation of momentum problems. An 80-kg quarterback jumps straight up in the air right before throwing a 0.43-kg football horizontally at 15 m/s. How fast will he be moving backward just after releasing the ball?

+1
Answers (1)
  1. 3 May, 18:38
    0
    0.081 m / s

    Explanation:

    According to the conservation of momentum, the momentum of a system is conserved when no external force is applied on a body.

    momentum of the system before throwing = momentum of the system after throwing

    Let v be the velocity of quarterback after throwing the football.

    80 x 0 + 0.43 x 0 = 80 x v + 0.43 x 15

    0 = 80 v + 6.45

    v = - 0.081 m / s

    The negative sign shows that he is moving in backward direction.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “To practice Problem-Solving Strategy 11.1 for conservation of momentum problems. An 80-kg quarterback jumps straight up in the air right ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers