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11 August, 19:27

You then decide to throw another disc to your friend in the tree for fun. If you throw the disc at a speed of 10 m/s and your friend catches it 5.0 m above you, what was the speed of the disc just before your friend catches it

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  1. 11 August, 19:35
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    Vf = 1.41 m/s

    Explanation:

    The velocity of the disc just before the friend catches it, can be found out by using 3rd equation of motion, as follows:

    2gh = Vf² + Vi²

    where,

    g = - 9.8 m/s² (negative sign for upward motion)

    h = height = 5 m

    Vi = Initial Velocity = 10 m/s

    Vf = Final Velocity = ?

    Therefore,

    2 (-9.8 m/s²) (5 m) = Vf² - (10 m/s) ²

    Vf² = 100 m²/s² - 98 m²/s²

    Vf = √ (2 m²/s²)

    Vf = 1.41 m/s
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