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3 February, 15:29

What is the minimum work needed to push a 925-kg car 207 m up along a 14.5° incline? Ignore friction.

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  1. 3 February, 18:49
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    4.7 x 10⁵ J

    Explanation:

    m = mass of the car = 925 kg

    d = distance traveled parallel to incline = 207 m

    θ = angle of the slope = 14.5 deg

    Force applied to move the car up is given as

    F = mg Sinθ eq-1

    minimum work needed is given as

    W = F d

    using eq-1

    W = mgd Sinθ

    inserting the values

    W = (925) (9.8) (207) Sin14.5

    W = 4.7 x 10⁵ J
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