Ask Question
5 April, 16:54

A 0.42 kg football is thrown with a velocity of 17 m/s to the right. A stationary receiver catches the ball and brings it to rest in 0.017 S. What is the force exerted on the receiver? Answer in units of N

+1
Answers (1)
  1. 5 April, 18:46
    0
    420 N

    Explanation:

    m = 0.42 Kg, u = 17 m/s, v = 0 m/s, t = 0.017 s

    By first law of Newtons' laws of motion, the rate of change in momentum is force, F = m (v - u) / t

    F = 0.42 x (0 - 17) / 0.017

    F = - 420 N

    Negative sign shows hat the force is resistive that means the ball finally comes to rest.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A 0.42 kg football is thrown with a velocity of 17 m/s to the right. A stationary receiver catches the ball and brings it to rest in 0.017 ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers