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14 December, 09:06

A person pushes a 16.0 kg lawn mower at constant speed with a force of 87.5 N directed along the handle, which is at an angle of 45.0 to the horizontal. Part D friction force? What force must the person exert on the lawn mower to accelerate it from rest to 1.3 m/s in 2.5 seconds, assuming the same Express your answer to three significant figures and Include the appropriate units

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  1. 14 December, 10:22
    0
    61.87 N

    99.3 N

    Explanation:

    Part D)

    Consider the forces acting on the lawnmower

    F = Applied force = 87.5 N

    θ = Angle of the applied force with the horizontal = 45

    m = mass of the lawnmower = 16 kg

    f = frictional force

    a = acceleration along the horizontal direction

    Force equation along the horizontal direction is given as

    F cosθ - f = ma

    (87.5) Cos45 - f = (16) (0)

    f = 61.87 N

    Part E)

    v₀ = initial velocity = 0 m/s

    v = final velocity = 1.3 m/s

    t = time interval = 2.5 sec

    a = acceleration

    using the equation

    v = v₀ + at

    1.3 = 0 + a (2.5)

    a = 0.52 m/s²

    Force equation along the horizontal direction is given as

    F cosθ - f = ma

    F Cos45 - 61.87 = (16) (0.52)

    F = 99.3 N
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