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10 August, 07:17

B. A hydraulic jack has a ram of 20 cm diameter and a plunger of 3 cm diameter. It is used for lifting a weight of 3 tons. Find the force required at the plunger.

a. 675.2kgf

b. 67.52kgf

c. 6752.0kgf

d. None of the above

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Answers (1)
  1. 10 August, 11:05
    0
    option (b)

    Explanation:

    According to the Pascal's law

    F / A = f / a

    Where, F is the force on ram, A be the area of ram, f be the force on plunger and a be the area of plunger.

    Diameter of ram, D = 20 cm, R = 20 / 2 = 10 cm

    A = π R^2 = π x 100 cm^2

    F = 3 tons = 3000 kgf

    diameter of plunger, d = 3 cm, r = 1.5 cm

    a = π x 2.25 cm^2

    Use Pascal's law

    3000 / π x 100 = f / π x 2.25

    f = 67.5 Kgf
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