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27 November, 17:23

What quantity of heat is needed to convert 1 kg of ice at - 13 degrees C to steam at 100 degrees C?

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  1. 27 November, 18:04
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    Heat energy needed = 3036.17 kJ

    Explanation:

    We have

    heat of fusion of water = 334 J/g

    heat of vaporization of water = 2257 J/g

    specific heat of ice = 2.09 J/g·°C

    specific heat of water = 4.18 J/g·°C

    specific heat of steam = 2.09 J/g·°C

    Here wee need to convert 1 kg ice from - 13°C to vapor at 100°C

    First the ice changes to - 13°C from 0°C, then it changes to water, then its temperature increases from 0°C to 100°C, then it changes to steam.

    Mass of water = 1000 g

    Heat energy required to change ice temperature from - 13°C to 0°C

    H₁ = mcΔT = 1000 x 2.09 x 13 = 27.17 kJ

    Heat energy required to change ice from 0°C to water at 0°C

    H₂ = mL = 1000 x 334 = 334 kJ

    Heat energy required to change water temperature from 0°C to 100°C

    H₃ = mcΔT = 1000 x 4.18 x 100 = 418 kJ

    Heat energy required to change water from 100°C to steam at 100°C

    H₄ = mL = 1000 x 2257 = 2257 kJ

    Total heat energy required

    H = H₁ + H₂ + H₃ + H₄ = 27.17 + 334 + 418 + 2257 = 3036.17 kJ

    Heat energy needed = 3036.17 kJ
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