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9 May, 08:41

The energy needed to keep a 75-watt lightbulb burning for 1.0 h is 270 kJ. Calculate the energy required to keep the lightbulb burning for 5.0 h in each of the following energy units. a) joules b) kilocalories

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  1. 9 May, 11:45
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    (a) 1.35 x 10^6 Joule

    (b) 321.45 Kcal

    Explanation:

    Energy consumed in 1 hour = 270 kJ

    So, Energy consumed in 5 hour = 270 x 5 = 1350 kJ

    (a) Energy in joules = 1350 x 1000 J = 1.35 x 10^6 J

    (b) 4.2 Joule = 1 calorie

    So, 1.35 x 10^6 Joule = 1.35 x 10^6 / 4.2 = 0.32 x 10^6 Calorie

    = 0.32 x 1000 Kcal = 321.45 Kcal
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