I have four questions.

: Consider a 2-kg bowling ball sits on top of a building that is 40 meters tall. It falls to the ground. Think about the amounts of potential and kinetic energy the bowling ball has:

• as it sits on top of a building that is 40 meters tall.

• as it is half way through a fall off a building that is 40 meters tall and travelling 19.8 meters per second.

• as it is just about to hit the ground from a fall off a building that is 40 meters tall and travelling 28 meters per second.

Number 1. What is the potential energy of the bowling ball as it sits on top of the building?

Number 2. What is the potential energy of the bowling ball half way through the fall?

Number 3. What is the kinetic energy of the ball half way through the fall?

Number 4. What is the kinetic energy of the ball just before it hits the ground?

Question

Physics

Kramer

8 June, 08:50

I have four questions.

: Consider a 2-kg bowling ball sits on top of a building that is 40 meters tall. It falls to the ground. Think about the amounts of potential and kinetic energy the bowling ball has:

• as it sits on top of a building that is 40 meters tall.

• as it is half way through a fall off a building that is 40 meters tall and travelling 19.8 meters per second.

• as it is just about to hit the ground from a fall off a building that is 40 meters tall and travelling 28 meters per second.

Number 1. What is the potential energy of the bowling ball as it sits on top of the building?

Number 2. What is the potential energy of the bowling ball half way through the fall?

Number 3. What is the kinetic energy of the ball half way through the fall?

Number 4. What is the kinetic energy of the ball just before it hits the ground?

+3

Answers (2)

Know the Answer?

Douglas Nielsen · Answer 1

Douglas Nielsen 8 June, 12:19

0

784 Jules, 392 Jules, 784 Jules

Mayo · Answer 2

The potential energy of the ball is 784 joules. And the kinetic energy of it is 392 while falling halfway down.

Explanation:

PE = mass (2kg) * Gravitational acceleration (9.8 m/s^2) * height (40 meters)

KE = 1/2 mass (1 kg) * velocity^2 (19.8)