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24 September, 23:19

Oil is poured into the open side of an open-tube manometer containing mercury. What is the density of the oil if a column of mercury 5.50 cm high supports a column of oil 85.0 cm high? (The density of mercury is 13,600 kg/m³)

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  1. 24 September, 23:28
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    880 kg / m^3

    Explanation:

    height of column of oil = 85 cm = 0.85 m

    height of column of mercury = 5.5 cm = 0.055 m

    Density of mercury = 13600 kg/m^2

    Let teh density of oil is d.

    A the height of mercury column is balanced by the height of oil column

    So, the pressure due to the mercury column = pressure by teh oil column

    height of mercury column x density of mercury x g = height of oil column

    x density of oil x g

    0.055 x 13600 x g = 0.85 x d x g

    748 = 0.85 d

    d = 880 kg / m^3
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