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Today, 13:31

A solid weighs 277.5 g in air and 212.5 g when totally immersed in the liquid of density 0.9 g / cc. Calculate the density of the solid.

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  1. Today, 14:12
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    3.842 g/cm³

    Explanation:

    Three forces are acting on the solid: weight, normal force (apparent weight), and buoyancy.

    ∑F = ma

    N - m g + ρf V g = 0

    N - ρs V g + ρf V g = 0

    ρs is the density of the solid and ρf is the density of the fluid it is submerged in.

    Writing normal force in terms of apparent mass, N = mₐ g:

    mₐ g - ρs V g + ρf V g = 0

    mₐ - ρs V + ρf V = 0

    mₐ = ρs V - ρf V

    mₐ = V (ρs - ρf)

    V = mₐ / (ρs - ρf)

    Volume is constant, so:

    mₐ / (ρs - ρf) = mₐ / (ρs - ρf)

    277.5 / (ρ - 0.0) = 212.5 / (ρ - 0.9)

    Cross multiply and solve:

    212.5ρ = 277.5 (ρ - 0.9)

    212.5ρ = 277.5ρ - 249.75

    249.75 = 65ρ

    ρ = 3.842

    The density of the solid is 3.842 g/cm³.
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