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3 November, 14:23

A projectile is launched with an initial velocity of 60.0 m/s at an angle of 30.0° above the horizontal. How far does it travel?

A) 152 m

B) 160 m

C) 184 m

D) 318 m

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Answers (2)
  1. 3 November, 15:00
    0
    D

    Explanation:

    The range is how far the projectile can go;

    R = U^2sin2A/g

    Where U is the initial velocity

    A is the angle of inclination

    =60^2sin2 (30) / 10 = 3600 sin60 / 10

    = 311.8m

    The exact answer should 312m
  2. 3 November, 16:16
    0
    Explanation: The initial velocity has two component v x and v y. The initial velocity in direction of y is given.
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