Ask Question
26 January, 11:49

In a classic carnival ride, patrons stand against the wall in a cylindrically shaped room. once the room gets spinning fast enough, the floor drops from the bottom of the room! friction between the walls of the room and the people on the ride make them the "stick" to the wall so they do not slide down. in one ride, the radius of the cylindrical room is r = 7.4 m and the room spins with a frequency of 21.1 revolutions per minute. 1) what is the speed of a person "stuck" to the wall?

+5
Answers (1)
  1. 26 January, 13:47
    0
    The answer is 14.8 m/s.

    Explanation:

    Substituting 22.1 revolutions for f, 6.4 meters for R in Relation between velocity and frequency of motion.

    V = (2π) (22.1) (6.4)

    = (2π) (22.1 rev / min) (1min: 60 s) (6.4)

    = 14.8 m/s.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “In a classic carnival ride, patrons stand against the wall in a cylindrically shaped room. once the room gets spinning fast enough, the ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers