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17 March, 21:00

What is the peak emf generated (in V) by rotating a 1000 turn, 42.0 cm diameter coil in the Earth's 5.00 ✕ 10-5 T magnetic field, given the plane of the coil is originally perpendicular to the Earth's field and is rotated to be parallel to the field in 12.0 ms?

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  1. 17 March, 23:46
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    5.77 Volt

    Explanation:

    N = 1000, Diameter = 42 cm = 0.42 m, t = 12 ms = 12 x 10^-3 s

    Change in magnetic field, B = 5 x 10^-5 T

    The peak value of emf is given by

    e = N x dФ / dt

    e = N x A x dB/dt

    e = (1000 x 3.14 x 0.21 x 0.21 x 5 x 10^-5) / (1.2 x 10^-3)

    e = 5.77 Volt
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