An elevator (mass 4850 kg) is to be designed so that the maximum acceleration is 0.0680g. What are the maximum and minimum forces the motor should exert on the supporting cable?

Where T is the tension in the cable, m is the mass of the elevator, and a is the acceleration; remember that the accel can be either up or down

max tension is needed to accelerate the elevator up:

T - 4850g=4850 (0.068g)

T=4850g (1+0.068) = 50762N

min tension:

T-4850g=-4850 (0.068)

T=4850g (1-0.068)

T=44,298N