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A 20 kg mass with an initial velocity of 10 m/s slides to a stop in 2 meters. What is the net work down on the mass? a.) 250 J b.) 500 J c.) 120 J d.) 20 J e.) None of the above

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  1. Today, 07:25
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    12500 J

    Explanation:

    m = 20 kg, u = 10 m/s, s = 2 m, v = 0

    Use third equation of motion

    v^2 = u^2 = 2 a s

    0 = 100 - 2 a x 2

    100 / 4 = - a

    a = - 25 m/s^2

    Force, F = m a = 20 x 25 = 500 N

    Work done = F x s = 500 x 25 = 12500 J
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