A piece of aluminum has a volume of 4.89 x 10-3 m3. The coefficient of volume expansion for aluminum is = 69 x 10-6 (C°) - 1. The temperature of this object is raised from 19.1 to 357 oC. How much work is done by the expanding aluminum if the air pressure is 1.01 x 105 Pa?

11.515 Joule

Explanation:

Volume of aluminium = V = 4.89*10⁻³ m³

Coefficient of volume expansion for aluminum = α = 69*10⁻⁶ / °C

Initial temperature = 19.1°C

Final temperature = 357°C

Pressure of air = 1.01*10⁵ Pa

Change in temperature = ΔT = 357-19.1 = 337.9 °C

Change in volume

ΔV = αVΔT

⇒ΔV = 69*10⁻⁶*4.89*10⁻³*337.9

⇒ΔV = 114010.839*10⁻⁹ m³

Work done

W = PΔV

⇒W = 1.01*10⁵*114010.839*10⁻⁹

⇒W = 11.515 J

∴ Work is done by the expanding aluminum is 11.515 Joule