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24 April, 23:02

A car travels at a constant speed around a circular track whose radius is 3.27 km. The car goes once around the track in 380 s. What is the magnitude of the centripetal acceleration of the car?

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  1. 25 April, 00:46
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    The magnitude of the centripetal acceleration of the car is 0.22 m/s².

    Explanation:

    t = 380 sec

    r = 3.27km = 3270m

    d=π*r=π*3270m

    d = 10273m

    d=Vt*t

    Vt = d/t = 10273m/380s

    Vt = 27.03 m/s

    ac = Vt²/r

    ac = (27.03 m/s) ²/3270m

    ac=0.22 m/s²
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