A 3.00-kg object undergoes an acceleration given by a = (2.00 i + 5.00 j) m/s^2. Find (a) the resultant force acting on the object and (b) the magnitude of the resultant force.

Question

Physics

Pearl

22 October, 17:55

A 3.00-kg object undergoes an acceleration given by a = (2.00 i + 5.00 j) m/s^2. Find (a) the resultant force acting on the object and (b) the magnitude of the resultant force.

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Answers (1)

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Reese Stanley · Answer 1

(a) : The resultant force acting on the object are F = (5.99 i + 14.98 j).

(b) : The magnitude of the resultant force are F = 16.4 N < 68.19º.

Explanation:

m = 3kg

a = 2 i + 5 j = 5.38 < 68.19 º

F = m * a

F = 3 * (5.38 < 68.19º)

F = 16.4 N < 68.19º

Fx = F * cos (68.19º)

Fx = 5.99

Fy = F * sin (68.19º)

Fy = 14.98