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24 April, 03:29

A 5.0 kilogram rock rolls off the edge of a cliff. If it is traveling at a speed of 24.2m/s when it hits the ground, what is the height of the cliff?

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  1. 24 April, 05:45
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    Using the kinematic equation;

    vf²=vi²+2ad just rearrange for d;

    vf²-vi²=2ad;

    (vf²-vi²) / 2a=d

    Now plug the numbers in.

    vf=24.2

    vi=0

    a=9.81=g

    (24.2²-0²) / (2*9.81) = 29.8 m.
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