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5 February, 19:49

A stone is thrown vertically upwards with a speed of 30.0 m/s.

(a) what's its speed when it reaches 20.0 meters?

(b) What is the maximum height?

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  1. 5 February, 20:21
    0
    a)

    Y₀ = initial position of the stone at the time of launch = 0 m

    Y = final position of stone = 20.0 meters

    a = acceleration = - 9.8 m/s²

    v₀ = initial speed of stone at the time of launch = 30.0 m/s

    v = final speed = ?

    Using the equation

    v² = v₀² + 2 a (Y - Y₀)

    inserting the values

    v² = 30² + 2 ( - 9.8) (20 - 0)

    v = 22.5 m/s

    b)

    Y₀ = initial position of the stone at the time of launch = 0 m

    Y = maximum height gained

    a = acceleration = - 9.8 m/s²

    v₀ = initial speed of stone at the time of launch = 30.0 m/s

    v = final speed = 0 m/s

    Using the equation

    v² = v₀² + 2 a (Y - Y₀)

    inserting the values

    0² = 30² + 2 ( - 9.8) (Y - 0)

    Y = 46 m
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