A child of mass 48.7 kg sits on the edge of a merry-go-round with radius 3 m and moment of inertia 376.938 kg m^2. The merry-go-round rotates with an angular velocity of 2.5 rad/s. What radial force does the child have to exert to stay on the merry-go-round? Answer in units of N.

913.125 N

Explanation:

From the question,

Applying

Fc = mω²r ... Equation 1

Where Fc = radial force of the child, m = mass of the child, ω = angular velocity, r = radius of the merry go round.

Given: m = 48.7 kg, ω = 2.5 rad/s, r = 3 m

Substitute into equation 1

Fc = 48.7 (2.5²) (3)

Fc = 48.7*6.25*3

Fc = 913.125 N

Hence the radial force the child have to exert to stay on the merry-go-round = 913.125 N