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30 October, 10:48

a cricket ball is thrown vertically upward with an intial velocity of 4ms-1 find. a. Its velocity after three second. b. maximum height attained and the time taken to reach it

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  1. 30 October, 12:35
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    a) - 25.43 m/s

    b) H = 0.815 m

    t = 0.41 s

    Explanation:

    Given that:

    Initial velocity (u) = 4 m/s, and the acceleration due to gravity (g) = 9.81 m/s²

    a) For a body thrown upward, gravity acts on the body and causes a decrease in velocity as it continues to move, making the body to reach a maximum height and start falling. The formula for a vertically thrown object is:

    v = u - gt

    t = time = 3 s and v = final velocity.

    Therefore:

    v = 4 - (9.81 * 3) = - 25.43 m/s

    b) The equation is given as:

    v² = u² - 2gH

    Where H is the maximum height. At maximum height, final velocity v = 0. Therefore:

    2gH = u²

    H = u² / 2g

    H = 4² / 2 (9.81) = 0.815 m

    Given that v = u - gt and at maximum height, v = 0

    Therefore t = u / g = 4 / 9.81 = 0.41 s
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