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5 May, 08:56

An 80.0 kg man sits on a scale in his car. The car is driving at a speed of 11.0 m/s right as it passes over the top of a semicircular hill of radius 17.0 m. What does the scale read right when he is at the top

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  1. 5 May, 09:53
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    F / g = 138 kg

    Explanation:

    For this exercise let's use Newton's second law

    F - W = m a

    the force is equal to the back of the balance

    in this case the acceleration is centripetal

    a = v² / r

    we substitute

    F - m g = m v² / r

    F = m (g + v² / r)

    calculus

    F = 80 (9.8 + 11²/17)

    F = 1353 N

    the balance reading is this value between gravity

    F / g = 1353 / 9.8

    F / g = 138 kg
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