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28 November, 13:18

A box with a mass of 2 kg accelerates in a straight line

from 4 m/s to 8 m/s due to the application of a force

whose duration is 0.5 s. Find the average strength of this

force.

+2
Answers (1)
  1. 28 November, 14:08
    0
    Answer: 16N

    Explanation:

    Given that:

    mass of box M = 2 kg

    Initial speed V1 = 4 m/s

    Final speed V2 = 8 m/s

    Time taken T = 0.5 s

    Average strength of this force F = ?

    Now, recall that Force is the rate of change of momentum per unit time

    i. e Force = momentum / time

    Hence, F = M x (V2 - V1) / T

    F = 2kg x (8 m/s - 4 m/s) / 0.5s

    F = 2kg x (4 m/s / 0.5s)

    F = 2kg x 8 m/s/s)

    F = 16N

    Thus, the average strength of this

    force is 16 newton.
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