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13 April, 04:16

A spherical conductor with a 0.103 m radius is initially uncharged. How many electrons should be removed from the sphere in order for it to have an electrical potential of 4.50 kV at the surface

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  1. 13 April, 06:03
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    capacitance of the capacitor C = 4πε₀R

    = 1 x. 103 / (9 x 10⁹) [ 1 / 4πε₀ = 9 x 10⁹. ]

    =.0114 x 10⁻⁹ F

    potential V = 4.5 x 10³ v

    charge Q = CV

    .0114 x 10⁻⁹ x 4.5 x 10³

    =.0515 x 10⁻⁶ C

    charge on one electron = 1.6 x 10⁻¹⁹

    no of electrons to be removed

    =.0515 x 10⁻⁶ / 1.6 x 10⁻¹⁹

    =.032 x 10¹³

    3.2 x 10¹¹ electrons.
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