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29 January, 16:45

15) A 328-kg car moving at 19.1 m/s in the + x direction hits from behind a second car moving at 13 m/s in the same direction. If the second car has a mass of 790 kg and a speed of 15.1 m/s right after the collision, what is the velocity of the first car after this sudden collision

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  1. 29 January, 20:39
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    Given that,

    Mass of first car

    M1 = 328kg

    The car is moving in positive direction of x axis with velocity

    U1 = 19.1m/s

    Velocity of second car

    U2 = 13m/s, in the same direction as the first car ...

    Mass of second car

    M2 = 790kg

    Velocity of second car after collision

    V2 = 15.1 m/s

    Velocity of first car after collision

    V1 = ?

    This is an elastic collision,

    And using the conservation of momentum principle

    Momentum before collision is equal to momentum after collision

    P (before) = P (after)

    M1•U1 + M2•U2 = M1•V1 + M2•V2

    328 * 19.1 + 790 * 13 = 328 * V1 + 790 * 15.1

    16534.8 = 328•V1 + 11929

    328•V1 = 16534.8-11929

    328•V1 = 4605.8

    V1 = 4605.8/328

    V1 = 14.04 m/s

    The velocity of the first car after collision is 14.04 m/s
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