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18 January, 06:10

An elevator car, with a mass of 450 kg is suspended by a single cable. At time = 0s, the elevator car is raised upward. The tension on the cable is constant at 5000N during the first 3 seconds of operation. Determine the magnitude of the velocity of the elevator at time = 3 seconds.

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  1. 18 January, 06:25
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    33.33 m/s

    Explanation:

    m = 450 kg. T = 5000 N, t = 3 seconds,

    let the net acceleration is a.

    T = m a

    a = 5000 / 450 = 11.11 m/s^2

    u = 0, v = ?

    Let v be the velocity after 3 seconds.

    Use first equation of motion

    v = u + a t

    v = 0 + 11.11 x 3 = 33.33 m/s
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