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23 September, 19:14

Your high-fidelity amplifier has one output for a speaker of resistance 8 Ω. How can you arrange two 8-Ω speakers, one 4-Ω speaker, and one 12-Ω speaker so that the amplifier powers all speakers and their equivalent resistance when connected together in this way is 8 Ω? Compare the power output of your arrangement with the power output of a single 8-Ω speaker.

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  1. 23 September, 21:25
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    (a) 8Ω (b) Ratio = Parra/P8 ohm = 1

    Explanation:

    Solution

    Recall that,

    An high-fidelity amplifier has one output for a speaker of resistance of = 8 Ω

    Now,

    (a) How can two 8-Ω speakers be arranged, when one = 4-Ω speaker, and one = 12-Ω speaker

    The Upper arm is : 8 ohm, 8 ohm

    The Lower arm is : 12 ohm, 4 ohm

    The Requirement is = (16 x 16) / (16 + 16) = 8 ohm

    (b) compare your arrangement power output of with the power output of a single 8-Ω speaker

    The Ratio = Parra/P8 ohm = 1
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