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1 July, 16:30

A box of mass?=21.0 kgm=21.0 kg is pulled up a ramp that is inclined at an angle?=21.0∘θ=21.0∘ angle with respect to the horizontal. The coefficient of kinetic friction between the box and the ramp is? k=0.285μk=0.285, and the rope pulling the box is parallel to the ramp. If the box accelerates up the ramp at a rate of?=2.09 m/s2a=2.09 m/s2, calculate the tension? TFT in the rope. Use?=9.81 m/s2g=9.81 m/s2 for the acceleration due to gravity.

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  1. 1 July, 17:27
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    The tension of the rope is T = 172.52 N

    Explanation:

    m = 21 kg

    α = 21º

    μ = 0.285

    a = 2.09 m/s²

    g = 9.81 m/s²

    W = m*g

    W=206.01 N

    Fr = μ*W*cos (α)

    Fr = 54.81 N

    Fx = W * sin (α)

    Fx = 73.82 N

    T-Fr-Fx = m*a

    T = m*a + Fr + Fx

    T = 172.52 N
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