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11 May, 21:39

A block of mass m = 4.8 kg slides from left to right across a frictionless surface with a speed Vi=7.3m/s. It collides with a block of mass M = 11.5 kg that is at rest. After the collision, the 4.8-kg block reverses direction, and its new speed is Vf=2.5m/s. What is V, the speed of the 11.5-kg block? 5.6 m/s

6.5 m/s

3.7 m/s

4.7 m/s

4.1 m/s

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  1. 11 May, 23:54
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    The speed of the 11.5kg block after the collision is V≅4.1 m/s

    Explanation:

    ma = 4.8 kg

    va1 = 7.3 m/s

    va2 = - 2.5 m/s

    mb = 11.5 kg

    vb1 = 0 m/s

    vb2=?

    vb2 = (ma*va1 - ma*va2) / mb

    vb2 = 4.09 m/s ≅ 4.1 m/s
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