An LC circuit has a 6.00 mH inductor. The current has its maximum value of 0.570 A at t = 0s. A short time later the capacitor reaches its maximum potential difference of 66.0 V. What is the value of the capacitance?

C = 44.75 x 10⁻⁸ F

Explanation:

Assuming no loss of energy between capacitor and inductor

energy in inductor initially = 1/2 Li₀² where L is inductance and i₀ is peak current.

=.5 x 6 x 10⁻³ x. 57²

=.97 x 10⁻³ J.

This energy is transferred to capacitor.

energy of capacitor = 1/2 CV²

=.5 x C x 66²

= 2178 C

2178C =.97 x 10⁻³

C = 44.75 x 10⁻⁸ F.