A thin beam of light of wavelength 625 nm goes through a thin slit and falls on a screen 3.00 m past the slit. You observe that the first completely dark fringes occur on the screen at distances of ±8.24 mm from the central bright fringe, and that the central bright fringe has an intensity of 2.00 W/m2 at its center. (a) How wide is the slit?

a = 2.275 10⁻⁴ m

Explanation:

This is a diffraction problem that is described by the equation

a sin θ = m λ

The first dark minimum occurs for m = 1

a = λ / sin θ

The angle can be found by trigonometry,

tan θ = y / x

θ = tan⁻¹ y / x

Let's reduce the magnitudes to the SI system

y = 8.24 mm = 8.24 10⁻³ m

λ = 625 nm = 625 10⁻⁹ m

θ = tan⁻¹ 8.24 10⁻³ / 3.00

θ = 0.002747 rad

We calculate

a = 625 10⁻⁹ / sin 0.002747

a = 2.275 10⁻⁴ m