A sail boat moves north for a distance of 10 km when blown by a wind 30° east of south with the force of 5.00*10^4 N. how much work was done by the wind?

a) 5.00 x 10^8 J

b) 2.50 x 10^8 J

c) 0.00 J

d) 4.33 x 10^8 J

Question

Physics

Guest

7 February, 02:55

A sail boat moves north for a distance of 10 km when blown by a wind 30° east of south with the force of 5.00*10^4 N. how much work was done by the wind?

a) 5.00 x 10^8 J

b) 2.50 x 10^8 J

c) 0.00 J

d) 4.33 x 10^8 J

+2

Answers (1)

Know the Answer?

Evangeline Allison · Answer 1

Answer;

a) 5.00 x 10^8 J

Explanation;

The work done to move the sailboat is calculated through the equation;

W = F x d

where F is force and d is the distance.

Substituting the known values from the given above,

W = (5.00 x 10⁴ N) (10 km) (1000 m / 1km)

= 5.00 x 10⁸ J

Thus, the work done is 5.00 x 10⁸Joules

A sail boat moves north for a distance of 10 km when blown by a wind 30° east of south with the force of 5.00*10^4 N. how much work was done by the wind?a) 5.00 x 10^8 Jb) 2.50 x 10^8 Jc) 0.00 Jd) 4.33 x 10^8 J

A sail boat moves north for a distance of 10 km when blown by a wind 30° east of south with the force of 5.00*10^4 N. how much work was done by the wind?

a) 5.00 x 10^8 J

b) 2.50 x 10^8 J

c) 0.00 J

d) 4.33 x 10^8 J