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11 November, 16:40

A car moving at 11.6 m/s begins to accelerate at 5.22 m/s/s and reaches a final velocity of 31.5 m/s. How far did it travel during this acceleration?

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  1. 11 November, 20:15
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    Use the kinematic equation,

    Vf^2 = Vi^2 + 2aX

    31.5^2 = 11.6^2 + 2 (5.22) (x)

    Solve for x

    Answer: 82.2m
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