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11 October, 14:10

An airplane flies eastward and always accelerates at a constant rate. At one position along its path it has a velocity of 34.3 m/s, it then flies a further distance of 40100 m and afterwards its velocity is 47.5 m/s. Find the airplane/'s acceleration and calculate how much time elapses while the airplane covers those 40100 m.

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  1. 11 October, 17:42
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    We'll need two equations.

    v² = v₀² + 2a (x - x₀)

    where v is the final velocity, v₀ is the initial velocity, a is the acceleration, x is the final position, and x₀ is the initial position.

    x = x₀ + ½ (v + v₀) t

    where t is time.

    Given:

    v = 47.5 m/s

    v₀ = 34.3 m/s

    x - x₀ = 40100 m

    Find: a and t

    (47.5) ² = (34.3) ² + 2a (40100)

    a = 0.0135 m/s²

    40100 = ½ (47.5 + 34.3) t

    t = 980 s
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