A spring with a constant of 16 N/m has 98 J of energy stored in it when it is extended. How far is the spring extended?

The spring has been extended for 3.5 m

Explanation:

We have the formula,

PE = 1/2 K X²

Rewrite the equation as

PE=1/2 K d²

multiply both the sides by 2/K to simplify the equation

2/k. PE = 1/2 K d². 2/K

√d²=√2PE/K

Cancelling the root value and now we have,

d=√2PE/k

d=√2*98 J / 16N/m

d=√12.25

d=3.5 m

The spring has been extended for 3.5 m