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18 December, 00:41

Two particles of equal masses are revolving circular path of radius r1 and r2 respectively with the same period.

The ratio of their centripetal force is: ... ?

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  1. 18 December, 01:49
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    Explanation & answer:

    F=mr (omega) ^2

    Here period is the same, and masses are equal, so

    m1=m2=m

    omega1=omega2=omega

    So

    F1/F2 = m (r1) (omega) ^2/m (r2) (omega) ^2 = r1/r2

    so the forces are proportional to their radii.
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