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5 March, 20:55

a ball was projected in such a way that it attained the maximum horizontal distance with a velocity of 20m/s calculate the vertical distance reached

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  1. 5 March, 21:02
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    80m

    Explanation:

    u=20, R=?, sin theta=1, g=10

    R=u²sin2theta/g

    R=20²x2/10

    R=400x2=800/10

    R=80m
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