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3 December, 03:45

How much force must a locomotive exert on a 12840-kg boxcar to make it accelerate forward at 0.490 m/s2?

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  1. 3 December, 04:42
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    Data given:

    m=12840kg

    a=0.490m/s²

    Formula:

    F=ma

    Solution:

    F = 12840kg*0.490m/s²

    F=6291.6N
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